CE En 544 - Exam #1 - SEEPAGE KEY

Winter Semester 2018

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Short Answer

Click here to access the equation sheet.

11. (1 pt) (seep-finelem) In a finite element mesh, a quadratic triangle would have nodes.

12. (seep-analytical) For the following flow net, assume

H1=20 ft,
H2 = 4 ft,
D = 30 ft,
HA = 15 ft,
k = 2e-4 cm/s

Use the bottom of the permeable layer as the datum for your head values in parts d and e.



a. (1 pt) How many equipotential drops are there?

b. (1 pt) How many flow channels are there?

c. (3 pts) Compute the flow rate beneath the dam. [ft^3/s/ft].

d. (1.5 pts) What is the total head at point A? [ft]

e. (1 pt) What is the pressure head at point A? [ft]

f. (1 pt) What is the pore pressure at point A? [psf]

13. (1 pt) (seep-dewater) A gravel-filled trench with a drainage pipe at the the bottom is called a(n) .

14. (3 pts) (seep-goveq) What were the three primary assumptions we made when deriving the governing differential equation?



15. (1 pt) (seep-head, darcy) Seepage velocity is than Darcy velocity.

16. (1 pt) (seep-head, darcy) The minor principal axis of permeability is to the bedding planes in a layered system.

17. (1 pt) (seep-head, darcy) There are three components of head as defined by Bernoulli's equation. In seepage/groundwater problems we typically ignore the head.